Determine geometry of flower pot surface?

Starting with a flat piece of paper, I want to cut out a shape such that it forms a "sleeve" for a flower pot; that is, when I wrap the shape around the outside of the pot, it should completely cover the surface of the pot.





The flower pot is 6 inches tall; the diameter at the top is 6 inches, and the diamater at the bottom is 4 inches. It's been awhile since my last geometry and trig classes, but here's what (I think) I know:


* the shape needs to look something like the rind of a watermelon slice.


* the length of the longer arc in the shape is 6*pi.


* the length of the shorter arc is 4*pi.


* the two arcs are about 5.75 inches apart.





How can I accurately draw this shape on the flat piece of paper, knowing the information above? What tools do I need (e.g., a protractor, compass, etc.)? For the record, I ended up just rolling the pot up in the paper and crudely drawing where I needed to cut, but I was curious as to how I would "formally" go about this.

Determine geometry of flower pot surface?
Your interest is highly appreciated!


the topic is slightly advanced and is part of engineering drawing;you can easily imagine that a rectangle is what you get if you open out a cylinder's surface;this is called 'development of surface of solids';in the case of a flower pot you have a truncated cone, that is , a cone whose top portion has been partly chopped off.


Please refer :


First year engineering drawing by A C PARKINSON;


OR


Elementary engineering drawing by N D BHATT


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